document.write( "Question 1133274: Urn 1 contains 6 red balls and 5 black balls. Urn 2 contains 3 red balls and 3 black balls. Urn 2 contains 3 red balls and 3 black balls. Urn 3 contains 2 red balls and 6 black balls. If an urn is selected at random and a ball is drawn, find the probability it will be red \n" ); document.write( "
Algebra.Com's Answer #750451 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! probability is 1/3 for each urn. \n" ); document.write( "for urn 1: (1/3)(6/11)=6/33 or 2/11 \n" ); document.write( "for urn 2:(1/3)(1/2)=1/6 \n" ); document.write( "for urn 3:(1/3)(1/3)=1/9 \n" ); document.write( "The probability is the sum with LCD 198 \n" ); document.write( "(1/198)(36+33+22)or 91/198 or 0.4596 \n" ); document.write( " |