document.write( "Question 1133236: A Year hence a Father will be Five times as Old as his Son. Two years ago , The father was 3 times as old his son will be four years hence. Find their Present age \n" ); document.write( "
Algebra.Com's Answer #750431 by addingup(3677)\"\" \"About 
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F + 1 = 5S
\n" ); document.write( "F = 5S - 1
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\n" ); document.write( "F - 2 = 3(S + 4)
\n" ); document.write( "F - 2 = 3S + 12
\n" ); document.write( "F = 3S + 14
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\n" ); document.write( "5S - 1 = 3S + 14
\n" ); document.write( "2S = 15
\n" ); document.write( "S = 7 1/2 or 7.5
\n" ); document.write( "The son is 7 1/2 years old, and the father is:
\n" ); document.write( "(5 x 7.5) - 1 = 37.5 - 1 = 36 1/2 years old
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\n" ); document.write( "Check
\n" ); document.write( "first equality given by the problem:
\n" ); document.write( "\"A Year hence a Father will be Five times as Old as his Son\"
\n" ); document.write( "36.5 + 1 = 5(7.5)
\n" ); document.write( "37.5 = 37.5 Correct
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\n" ); document.write( "second equality given by the problem:
\n" ); document.write( "\"Two years ago , The father was 3 times as old his son will be four years hence\"
\n" ); document.write( "F - 2 = 3(S+4)
\n" ); document.write( "36.5 - 2 = 3(7.5 + 4)
\n" ); document.write( "34.5 = 3 x 11.5
\n" ); document.write( "34.5 = 34.5 Correct\r
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