document.write( "Question 1133203: A soccer team goes to Starr Burger after a game. The number of drinks ordered is 2 less than the number of burgers. If burgers cost $3.25 and drinks cost $1.50, how many of each were ordered if the coach paid a total of $49.25? \n" ); document.write( "
Algebra.Com's Answer #750405 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Algebra.... \n" ); document.write( "let x be the number of burgers; then x-2 is the number of drinks. The total, at $3.25 per burger and $1.50 per drink, is $49.25: \n" ); document.write( " \n" ); document.write( "Solve the equation using basic algebra. \n" ); document.write( "Using logic and mental arithmetic.... \n" ); document.write( "(1) Imagine ordering 2 more drinks, at $1.50 each, making the number of drinks equal to the number of burgers, and making the new total $52.25. \n" ); document.write( "(2) One drink and one burger together cost $4.75. Do the mental arithmetic to see that the number of burgers and drinks that costs $52.25 is 11. (i.e., calculate 52.25/4.75 = 11) \n" ); document.write( "(3) So the number of burgers is 11; take away those 2 other drinks that the coach didn't really order, and the number of drinks is 11-2 = 9. \n" ); document.write( " |