document.write( "Question 1133222: Solve x-3/x-5 >= 0 for x and graph the solution on a number line. \n" ); document.write( "
Algebra.Com's Answer #750395 by ikleyn(52797)\"\" \"About 
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document.write( "\"%28x-3%29%2F%28x-5%29\" >= 0.\r\n" );
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document.write( "In this problem, there are two values of x, where the binomials in the numerator and denominator change their signs.\r\n" );
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document.write( "These values are x= 3  and  x= 5.\r\n" );
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document.write( "Notice that the domain of this inequality is the entire number line except of the value x= 5, where the denominator is zero.\r\n" );
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document.write( "The values (the points) 3 and 5 divide the number line (or, better to say, the domain) in three intervals:\r\n" );
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document.write( "    -infinity < x <=3;   3 <= x < 5   and  5 < x < infinity.\r\n" );
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document.write( "At the interval  -infinity < x <=3,  the numerator  (x-3) is negative; the denominator (x-5) is negative, too;  \r\n" );
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document.write( "hence, the fraction is positive.  Thus  the entire interval (\"-infinity\",\"3\"] is the part of the solution.\r\n" );
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document.write( "At the interval  3 <= x < 5,  the numerator  (x-3) is positive; the denominator (x-5) is negative;  \r\n" );
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document.write( "hence, the fraction is negative.  Thus  the entire interval [\"3\",\"5\") is NOT the part of the solution.\r\n" );
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document.write( "At the interval  5 < x < infinity,  the numerator  (x-3) is positive; the denominator (x-5) is positive;  \r\n" );
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document.write( "hence, the fraction is positive.  Thus  the entire interval (\"5\",\"infinity\") is the part of the solution.\r\n" );
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document.write( "ANSWER.  The solution to the given inequality is the union of two intervals   (\"-infinity\",\"3\"] U (\"5\",\"infinity\").\r\n" );
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