document.write( "Question 1133213: A rabbit was 60 of her own leaps in front, while being chased by a dog, and took three leaps while the dog took two. But the dog went as far in three leaps as the rabbit did in seven.
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Algebra.Com's Answer #750384 by ikleyn(52776)\"\" \"About 
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document.write( "The rabbit makes 3 jumps at the same time as the dog makes 2 jumps.\r\n" );
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document.write( "Hence, the rabbit makes 9 jumps at the same time as the dog makes 6 jumps.\r\n" );
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document.write( "But 6 dog's jumps equate to 14 rabbit's jumps.\r\n" );
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document.write( "Hence, at the same time as rabbit makes 9 jumps, the dog moves forward for the distance of 14 rabbit's jumps.\r\n" );
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document.write( "Thus every time as the rabbit moves forward for his 9 jumps, the dog is in 5 = 14 - 9 rabbit's jumps closer to him.\r\n" );
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document.write( "It implies that as soon as the rabbit completes his 9*12-th jump (= 108-th jump), the dog will catch up the rabbit.   \r\n" );
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document.write( "    Notice 12 = 60/5.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answer.  As soon as the rabbit makes his  108-th jump,  the dog will catch up the rabbit.\r
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\n" ); document.write( "\n" ); document.write( "Or,  in the terms of dog's jumps,  as soon as the dog makes his  6*12 = 72-th jump,  the dog will catch up the rabbit. \r
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\n" ); document.write( "\n" ); document.write( "To see other similar solved problem, look into the lesson\r
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