document.write( "Question 1133165: 8;18;30:44\r
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Algebra.Com's Answer #750353 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "I will copy the very good response from tutor @MathLover1 and expand on it a bit....

\n" ); document.write( "\"8\",\"18\",\"30\",\"44\" -> find differences first\r
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\n" ); document.write( "\n" ); document.write( "I revised and added some to this display....
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document.write( "     8      18      30      44     (the given sequence)\r\n" );
document.write( "        10      12      14         (the \"first\" differences -- differences between successive terms)\r\n" );
document.write( "            2       2              (the \"second differences -- differences between successive first differences)
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\n" ); document.write( "\n" ); document.write( "The pattern goes +\"10\", +\"12\", +\"14\", ...\r
\n" ); document.write( "\n" ); document.write( "Since the second difference is always +\"2\", the nth term must involve \"n%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "I'll add a lot here, assuming you are not familiar with what she says there.

\n" ); document.write( "In this problem, the second differences are a constant 2, which is 2!. In general, if the second differences are a constant 2k, then the sequence can be produced by a polynomial with leading term kx^2. So, for example, if you have a similar problem where the constant second differences are 8, the sequence can be produced by a polynomial with leading term 4x^2.

\n" ); document.write( "The idea continues for polynomials of higher degrees:

\n" ); document.write( "If the polynomial has leading term kx^3, then the constant 3rd differences will be 6k (where 6 = 3!).

\n" ); document.write( "If the polynomial has leading term kx^4, then the constant 4th differences will be 24k (where 24 = 4!).

\n" ); document.write( "And so on....
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\n" ); document.write( "\n" ); document.write( "So let's say the nth number in the sequence = \"n%5E2+%2B+an+%2B+b\"\r
\n" ); document.write( "\n" ); document.write( "To find \"b\", you can substitute in \"n=0\", i.e. what is the \"zeroth\" number in the sequence? In other words, what number would have come before \"8\"?\r
\n" ); document.write( "\n" ); document.write( "This number must have been \"0\", in order to continue the pattern of +\"8\", +\"10\", +\"12\", +\"14\", ...\r
\n" ); document.write( "\n" ); document.write( "So we now know the nth number = \"n%5E2+%2B+an\"\r
\n" ); document.write( "\n" ); document.write( "Now just plug in any other value we know, to find the value of\"+a\". For example, using the first number in the sequence (\"n=1\"), we get:
\n" ); document.write( "\"1+%2B+a+=+8\"
\n" ); document.write( "\"a+=+7\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore the nth term in this sequence is: \"n%5E2+%2B+7n+\"
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