document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1133171>Question 1133171</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man waters, with a garden hose, a contained area of 2.26 feet. If the volume of water coming out of the hose fills a 10 quart pail in 2 minutes, what is the \"rainfall\" depth (in inches) equivalent if he runs the hose for 12 minutes? \r<BR>\n" );
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document.write( "Show all work. Some conversion factors you may need: \r<BR>\n" );
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document.write( "1 gallon = 8 pounds <BR>\n" );
document.write( "1 cubic foot = 62.4 pounds <BR>\n" );
document.write( "(pi) r^2 h = volume of a cylinder <BR>\n" );
document.write( "d = 2r  </SPAN>\n" );
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document.write( "I will assume the contained area is 2.26 SQUARE feet....<br><BR>\n" );
document.write( "Use the given flow rate and the given amount of time to determine the number of cubic feet of water; the depth (in feet) is that volume of water, divided by the area.  Then convert the answer in feet to inches.<br><BR>\n" );
document.write( "The conversion can be accomplished using several unit multipliers.<br><BR>\n" );
document.write( "Volume of water in 12 minutes:<br><PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\">\r\n" );
document.write( "            10 qt     1 gal     8 pounds       1 cu ft\r\n" );
document.write( "  12 min * ------- * ------- * ---------- * -------------\r\n" );
document.write( "            2 min     4 qt        1 gal      62.4 pounds<br></PRE><BR>\n" );
document.write( "Then divide by the area to get the depth in feet; then multiply by 12 to get the depth in inches. </SPAN>\n" );
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