document.write( "Question 1133165: 8;18;30:44\r
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Algebra.Com's Answer #750347 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"8\",\"18\",\"30\",\"44\" -> find differences first\r
\n" ); document.write( "\n" ); document.write( "\"8\".........\"18\"..........\"30\"..........\"44\"
\n" ); document.write( ".....\"10\".........\"12\"...........\"14\"\r
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\n" ); document.write( "\n" ); document.write( "The pattern goes +\"10\", +\"12\", +\"14\", ...\r
\n" ); document.write( "\n" ); document.write( "Since the second difference is always +\"2\", the nth term must involve \"n%5E2\".\r
\n" ); document.write( "\n" ); document.write( "So let's say the nth number in the sequence = \"n%5E2+%2B+an+%2B+b\"\r
\n" ); document.write( "\n" ); document.write( "To find \"b\", you can substitute in \"n=0\", i.e. what is the \"zeroth\" number in the sequence? In other words, what number would have come before \"8\"?\r
\n" ); document.write( "\n" ); document.write( "This number must have been \"0\", in order to continue the pattern of +\"8\", +\"10\", +\"12\", +\"14\", ...\r
\n" ); document.write( "\n" ); document.write( "So we now know the nth number = \"n%5E2+%2B+an\"\r
\n" ); document.write( "\n" ); document.write( "Now just plug in any other value we know, to find the value of\"+a\". For example, using the first number in the sequence (\"n=1\"), we get:
\n" ); document.write( "\"1+%2B+a+=+8\"
\n" ); document.write( "\"a+=+7\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore the nth term in this sequence is: \"n%5E2+%2B+7n+\"\r
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