document.write( "Question 1133139: solve each proportion then find another equlivent ratio x over 15 is equal to 12 over 90
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Algebra.Com's Answer #750312 by josgarithmetic(39617)\"\" \"About 
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\"15%2Fx=12%2F90\"\r
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\n" ); document.write( "\n" ); document.write( "\"%2815%2Fx%29x=%2812%2F90%29x\"\r
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\n" ); document.write( "\n" ); document.write( "\"15=%2812%2F90%29x\"\r
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\n" ); document.write( "\n" ); document.write( "\"15%2890%2F12%29=x\"\r
\n" ); document.write( "\n" ); document.write( "\"15%283%2A30%29%2F%283%2A4%29=x\"\r
\n" ); document.write( "\n" ); document.write( "\"15%2830%2F4%29=x\"\r
\n" ); document.write( "\n" ); document.write( "\"15%2815%2F2%29=x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=112%261%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "ALTERNATIVE\r
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\n" ); document.write( "\n" ); document.write( "\"x%2F15=90%2F12\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2F15=%283%2A3%2A2%2A5%29%2F%283%2A4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2F%283%2A5%29%29=%283%2A5%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%28%283%2A5%29%5E2%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"x=225%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=112%261%2F2\"
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