document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1133117>Question 1133117</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One of the main contaminants of a nuclear accident, such as that at Chernobyl, is strontium-90, which decays exponentially at an annual rate of approximately 2.4% per year.\r<BR>\n" );
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document.write( "Write the percent of strontium-90 remaining, P, as a function of years, t, since the nuclear accident. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #750295 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=750295\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The exponential decay rate formula for this problem<BR>\n" );
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document.write( "P = a(1-b)^t, where P is the amount of strontium-90 remaining after the decay over a period of time, a is the original amount, b is the percent decrease in decimal form, and t is the time<BR>\n" );
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document.write( "For this problem, a is 1(100%), b is 0.024<BR>\n" );
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document.write( "P = 1(1-0.024)^t<BR>\n" );
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document.write( "P = 0.976^t<BR>\n" );
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