document.write( "Question 1133089: A group of workers won the lottery and will each walk away with $10 000. Fred, one of the workers, decides to spend some of the money and save the rest. He wants the money he saves to grow back into $10 000 in 7 years. He can invest the money at 5.5% compounded quarterly.\r
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\n" ); document.write( "\n" ); document.write( "a) How much must he invest to meet his goal.\r
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\n" ); document.write( "\n" ); document.write( "b) How much money can he afford to spend today?\r
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\n" ); document.write( "\n" ); document.write( "(I have been working on this problem and i did get for R=4657.65 and i am not sure what they mean by part b.)
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Algebra.Com's Answer #750266 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Part (a)\r
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\n" ); document.write( "\n" ); document.write( "We'll use the compound interest formula shown below\r
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\n" ); document.write( "\n" ); document.write( "A = P*(1+r/n)^(n*t)\r
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\n" ); document.write( "\n" ); document.write( "The variables are
\n" ); document.write( "A = final amount
\n" ); document.write( "P = initial amount (aka deposit)
\n" ); document.write( "r = annual interest rate in decimal form
\n" ); document.write( "n = number of times money is compounded per year
\n" ); document.write( "t = number of years\r
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\n" ); document.write( "\n" ); document.write( "In this case, we have,
\n" ); document.write( "A = 10000 is the final amount we want to have
\n" ); document.write( "P = unknown initial amount or deposit (what we want to solve for)
\n" ); document.write( "r = 0.055 is the decimal form of 5.5% (note how 5.5% = 5.5/100 = 0.055)
\n" ); document.write( "n = 4 means we compound 4 times a year, in other words, quarterly
\n" ); document.write( "t = 7 years pass by\r
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\n" ); document.write( "\n" ); document.write( "Let's plug those mentioned values into the formula. Solve for P.\r
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\n" ); document.write( "\n" ); document.write( "A = P*(1+r/n)^(n*t)
\n" ); document.write( "10000 = P*(1+0.055/4)^(4*7)
\n" ); document.write( "10000 = P*(1+0.01375)^(28)
\n" ); document.write( "10000 = P*(1.01375)^(28)
\n" ); document.write( "10000 = P*1.46576478021002
\n" ); document.write( "1.46576478021002*P = 10000
\n" ); document.write( "P = 10000/1.46576478021002
\n" ); document.write( "P = 6,822.37705190812
\n" ); document.write( "P = 6,822.38\r
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\n" ); document.write( "\n" ); document.write( "--------------------\r
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\n" ); document.write( "\n" ); document.write( "Answer: 6822.38 dollars\r
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\n" ); document.write( "\n" ); document.write( "Part (b)\r
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\n" ); document.write( "\n" ); document.write( "Whatever we found back in part (a) represents the amount needed to be put aside to save back to $10,000. The rest can be spent.
\n" ); document.write( "Subtract the result found in part (a) from 10,000 to get: 10,000 - 6,822.38 = 3,177.62\r
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\n" ); document.write( "\n" ); document.write( "Answer: 3177.62 dollars\r
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