document.write( "Question 1133073: A teacher has two students, one two times as old as the other. The teacher is five times as old as the older student, and in 5 years she will be five times as old as her younger student. Find the teacher’s present age.
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Algebra.Com's Answer #750245 by math_helper(2461)\"\" \"About 
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Let x= Age of younger student
\n" ); document.write( "Then
\n" ); document.write( "2x is the age of the older student
\n" ); document.write( "5(2x)=10x is the age of the teacher
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\n" ); document.write( "\n" ); document.write( "10x+5 = 5(x+5) \r
\n" ); document.write( "\n" ); document.write( "Solve the above for x to get x=4 —> teacher is 10x=40 years old\r
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\n" ); document.write( "Ans: the teacher is 40 years old
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\n" ); document.write( "Check:
\n" ); document.write( "Younger student is 4
\n" ); document.write( "Older student is 2*4=8
\n" ); document.write( "Teacher is 40 (=5*8, in agreement with teacher being 5 times as old as older student)
\n" ); document.write( "In 5 years,
\n" ); document.write( "Younger student will be 9
\n" ); document.write( "Teacher will be 45 (= 9*5, so this answer checks)
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