document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1133067>Question 1133067</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A jeweler has five rings, each weighing 18grams, made of an alloy of 10% silver and 90% gold. He decides to melt down the rings and add enough silver to reduce the gold content to 60%. How much silver should he add? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #750234 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=750234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 90 grams total with 9gm (10%) pure silver and 81gm (90%) pure gold.  After adding more silver, it will be 40%<BR>\n" );
document.write( "so (9+x)/(90+x)=2/5, which is 40%<BR>\n" );
document.write( "cross-multiply<BR>\n" );
document.write( "5(9+x)+2(90+x)<BR>\n" );
document.write( "45+5x=180+2x<BR>\n" );
document.write( "3x=135<BR>\n" );
document.write( "x=45gm silver ANSWER<BR>\n" );
document.write( "the total amount of metal will be 135 gm, and now 54 of that (9+45) will be silver.<BR>\n" );
document.write( "therefore, 81gm of the 135 will be gold and that is 60%.<BR>\n" );
document.write( " </SPAN>\n" );
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