document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1133030>Question 1133030</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two friction wheels are of diameter 20mm and 200mm respectively. they connect at P and rotate without slipping. calculate the number of turns made by the small wheel when the large wheel rotate through 60° </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #750182 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=750182\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the formula for circumfernce of a circle is 2 * pi * r or pi * d.\r<BR>\n" );
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document.write( "the small wheel has a diameter of 20 millimeters.<BR>\n" );
document.write( "the large wheel has a diameter of 200 millimeters.\r<BR>\n" );
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document.write( "the circumference of the small wheel is equal to 20 * pi millimeters.<BR>\n" );
document.write( "the circumference of the large wheel is equal to 200 * pi millimeters.\r<BR>\n" );
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document.write( "if the large wheel is rotating the small wheel, then the large wheel will make the small wheel turn 10 times for one turn of the large wheel.\r<BR>\n" );
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document.write( "one turn is equal to 360 degrees.\r<BR>\n" );
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document.write( "60 degrees is equal to 60 / 360 = 1/6 times one turn.\r<BR>\n" );
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document.write( "when the large wheel is rotating 1/6 of a turn, then the small wheel is rotating 10 * 1/6 of a turn which is equal to 10 / 6 turns\r<BR>\n" );
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document.write( "10 / 6 turns is equivalent to 5 / 3 turns.\r<BR>\n" );
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document.write( "1/6 turns of the large wheel therefore causes 1 and 2/3 turns of the small wheel.\r<BR>\n" );
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