document.write( "Question 1133014: Twins Joanie and Tony each start out with the same number of cents.
\n" ); document.write( "Joanie buys 1 candy bar and has 70 cents left.
\n" ); document.write( "Tony buys 3 candy bars at the same price and has 20 cents left
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Algebra.Com's Answer #750169 by Theo(13342)\"\" \"About 
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x equals the price of a candy bar.
\n" ); document.write( "y equals the amount of money they both started out with.\r
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\n" ); document.write( "\n" ); document.write( "your equations are:\r
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\n" ); document.write( "\n" ); document.write( "for joanie, y - x = 70\r
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\n" ); document.write( "\n" ); document.write( "for tony, y - 3x = 20\r
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\n" ); document.write( "\n" ); document.write( "these are two equations that need to be solved simultaneously.\r
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\n" ); document.write( "\n" ); document.write( "subtract the second equation from the first to get:\r
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\n" ); document.write( "\n" ); document.write( "2x = 50\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get x = 25\r
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\n" ); document.write( "\n" ); document.write( "for joanie, y - 25 = 70.\r
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\n" ); document.write( "\n" ); document.write( "solve for y to get y = 95 cents.\r
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\n" ); document.write( "\n" ); document.write( "for tony, y - 3 * 25 = 20 which becomes y - 75 = 20.\r
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\n" ); document.write( "\n" ); document.write( "solve for y to get y = 95 cents.\r
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\n" ); document.write( "\n" ); document.write( "they both started out with 95 cents.\r
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\n" ); document.write( "\n" ); document.write( "the price of one candy bar was 25 cents.\r
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\n" ); document.write( "\n" ); document.write( "95 - 25 = 70 which is what joanie had left.\r
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\n" ); document.write( "\n" ); document.write( "95 - 3 * 25 = 20 which is what tony had left.\r
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