document.write( "Question 1132941: Mr. Stein invested a total of $100,000 in two companies for a year. Company A’s stock showed a 13% annual
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Algebra.Com's Answer #750106 by ikleyn(52879)\"\" \"About 
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document.write( "Let x be the amount invested in company A' stock, in dollars.\r\n" );
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document.write( "Then the amount invested in company B' stock is  (100000-x) dollars.\r\n" );
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document.write( "Your basic equation is \r\n" );
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document.write( "    13% gain - 3% loss         = 8% return,    or\r\n" );
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document.write( "    0.13x    - 0.03*(100000-x) = 0.08*100000.\r\n" );
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document.write( "Simplify step by step and solve for x:\r\n" );
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document.write( "    0.13x - 3000 + 0.03x = 8000,\r\n" );
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document.write( "    0.16x = 8000 + 3000\r\n" );
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document.write( "    0.16x = 11000  ====>  x = \"11000%2F0.16\" = 68750.\r\n" );
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document.write( "ANSWER.  68750 dollars invested in company A' stock;  the rest,  100000 - 68750 = 31250 dollars invested in company B' stock.\r\n" );
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document.write( "CHECK.   0.13*68750 - 0.03*31250 = 8000 dollars.    ! Correct !\r\n" );
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