document.write( "Question 1132934: Mr.Santos is 25years older than his son, 8 years ago, he was 7 more than 10 times as old as his son.What are their present ages? \n" ); document.write( "
Algebra.Com's Answer #750102 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The difference in their ages will always be 25 years.

\n" ); document.write( "8 years ago, Mr. Santos was 7 more than 10 times as old as his son. If x was his son's age then, his age then was 10x+7; then the difference in their ages was (10x+7)-x = 9x+7.

\n" ); document.write( "So find when 9x+7 is equal to 25:

\n" ); document.write( "\"9x%2B7+=+25\"

\n" ); document.write( "Solve for x; that will be the son's age 8 years ago.

\n" ); document.write( "Then add 8 to get the son's current age; then add 25 to get Mr Santos's current age.
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