document.write( "Question 1132938: The length of a rectangle is
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\n" ); document.write( "If the perimeter of the rectangle is
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Algebra.Com's Answer #750097 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "if the length \"L\" of a rectangle is \"3ft\" longer than its width \"W\", we have\r
\n" ); document.write( "\n" ); document.write( "\"L=W%2B3ft\".......eq.1\r
\n" ); document.write( "\n" ); document.write( "if the perimeter \"P\" of the rectangle is \"70ft\", we have\r
\n" ); document.write( "\n" ); document.write( " \"P=2%28L%2BW%29\" \r
\n" ); document.write( "\n" ); document.write( "\"70ft=2%28L%2BW%29\"
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\n" ); document.write( "\"70ft%2F2=L%2BW\" \r
\n" ); document.write( "\n" ); document.write( "\"35ft=L%2BW\" ......eq.2\r
\n" ); document.write( "\n" ); document.write( "substitute \"L\" from eq.1 \r
\n" ); document.write( "\n" ); document.write( "\"35ft=W%2B3ft%2BW\" ......eq.2\r
\n" ); document.write( "\n" ); document.write( "\"35ft-3ft=2W\"\r
\n" ); document.write( "\n" ); document.write( "\"32ft=2W\"\r
\n" ); document.write( "\n" ); document.write( "\"W=++32ft%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"W=+16ft\"\r
\n" ); document.write( "\n" ); document.write( "go back to eq.1,substitute \"W\" \r
\n" ); document.write( "\n" ); document.write( "\"L=16ft%2B3ft\".......eq.1\r
\n" ); document.write( "\n" ); document.write( "\"L=19ft\"\r
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\n" ); document.write( "\n" ); document.write( "answer: its length is \"19ft\" and width is \"+16ft\"\r
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