document.write( "Question 1132886: Jack, Kay, and Lynn deliver advertising flyers in a small town. If each person works alone, it takes Jack 2 h to deliver all the flyers, and it takes Lynn 5 h longer than it takes Kay. Working together, they can deliver all the flyers in 60% of the time it takes Kay working alone. How long does it take Kay to deliver all the flyers alone? \n" ); document.write( "
Algebra.Com's Answer #750041 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Let k be the number of hours Kay takes to do the job alone; then k+5 is the number of hours it takes Lynn alone. We are given that it takes Jack 2 hours to do the job.

\n" ); document.write( "So the fractions the three of them do alone in 1 hour are 1/2, 1/k, and 1/(k+5).

\n" ); document.write( "Working together, it takes the three of them 60% as long as it takes Kay alone. Since it takes them 3/5 as long as Kay working alone, in 1 hour the fraction of the job they get done together is 5/3 as much as Kay alone does in 1 hour. Then the equation to solve is

\n" ); document.write( "\"1%2F2+%2B+1%2Fk+%2B+1%2F%28k%2B5%29+=+%285%2F3%29%281%2Fk%29\"

\n" ); document.write( "Multiply everything by the LCM of the denominators, 6k(k+5):

\n" ); document.write( "\"3k%28k%2B5%29%2B6%28k%2B5%29%2B6k+=+10%28k%2B5%29\"
\n" ); document.write( "\"3k%5E2%2B15k%2B6k%2B30%2B6k+=+10k%2B50\"
\n" ); document.write( "\"3k%5E2%2B17k-20+=+0\"
\n" ); document.write( "\"%283k%2B20%29%28k-1%29+=+0\"

\n" ); document.write( "Obviously choose the positive solution, k=1.

\n" ); document.write( "ANSWER: It takes Kay 1 hour to deliver all the flyers alone.
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