document.write( "Question 1132886: Jack, Kay, and Lynn deliver advertising flyers in a small town. If each person works alone, it takes Jack 2 h to deliver all the flyers, and it takes Lynn 5 h longer than it takes Kay. Working together, they can deliver all the flyers in 60% of the time it takes Kay working alone. How long does it take Kay to deliver all the flyers alone? \n" ); document.write( "
Algebra.Com's Answer #750041 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let k be the number of hours Kay takes to do the job alone; then k+5 is the number of hours it takes Lynn alone. We are given that it takes Jack 2 hours to do the job. \n" ); document.write( "So the fractions the three of them do alone in 1 hour are 1/2, 1/k, and 1/(k+5). \n" ); document.write( "Working together, it takes the three of them 60% as long as it takes Kay alone. Since it takes them 3/5 as long as Kay working alone, in 1 hour the fraction of the job they get done together is 5/3 as much as Kay alone does in 1 hour. Then the equation to solve is \n" ); document.write( " \n" ); document.write( "Multiply everything by the LCM of the denominators, 6k(k+5): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Obviously choose the positive solution, k=1. \n" ); document.write( "ANSWER: It takes Kay 1 hour to deliver all the flyers alone. \n" ); document.write( " |