document.write( "Question 1132829: Suppose that the lifetimes of light bulbs are approximately normally​ distributed, with a mean of 57 hours and a standard deviation of 3.5 hours. With this​ information, answer the following questions.What proportion of light bulbs will last more than 61 ​hours?
\n" ); document.write( "​(b) What proportion of light bulbs will last 52 hours or​ less?
\n" ); document.write( "​(c) What proportion of light bulbs will last between 57 and 62 ​hours?
\n" ); document.write( "​(d) What is the probability that a randomly selected light bulb lasts less than 46 ​hours
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Algebra.Com's Answer #749969 by Theo(13342)\"\" \"About 
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mean is 57 hours.
\n" ); document.write( "standard deviation is 3.5 hours.\r
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\n" ); document.write( "\n" ); document.write( "use the z-score to find the answer you need.
\n" ); document.write( "formula for z-score is z = (x - m) / s
\n" ); document.write( "z is the z-score
\n" ); document.write( "x is the raw score
\n" ); document.write( "m is the raw score mean
\n" ); document.write( "s is the standard deviation.\r
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\n" ); document.write( "\n" ); document.write( "(a) what proportion of light bulbs will last more than 61 hours.\r
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\n" ); document.write( "\n" ); document.write( "z = (61 - 57) / 3.5 = 1.142857143.
\n" ); document.write( "area to the right of that z-score is equal to .1265490059.
\n" ); document.write( "that's the probability of the life of the light bulb to be greater than 61.\r
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\n" ); document.write( "\n" ); document.write( "​(b) What proportion of light bulbs will last 52 hours or​ less?\r
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\n" ); document.write( "\n" ); document.write( "z = (52 - 57) / 3.5 = -1.428571429
\n" ); document.write( "area to the left of that z-score is equal to .0765637714.
\n" ); document.write( "that's the probability of the life of the light bulb to be less than 52.\r
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\n" ); document.write( "​(c) What proportion of light bulbs will last between 57 and 62 ​hours?\r
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\n" ); document.write( "\n" ); document.write( "the z-score for 57 is equal to (57 - 57) / 3.5 = 0
\n" ); document.write( "the z-score for 62 is equal to (62 - 57) / 3.5 = 1.428571429
\n" ); document.write( "the area to the left of a z-score of 0 is equal to .5
\n" ); document.write( "the area to the left of a z-score of 1.428571429 is equal to .9234362286.
\n" ); document.write( "the area between a z-score of 0 and a z-score of 1.428571429 is equal to .9234362286 minus .5 = .4234362286.
\n" ); document.write( "that's the probability of the life of the light bulb to be between 57 and 62 hours.\r
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\n" ); document.write( "\n" ); document.write( "​(d) What is the probability that a randomly selected light bulb lasts less than 46 ​hours\r
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\n" ); document.write( "\n" ); document.write( "z = (46 - 57) / 3.5 = -3.142857143.
\n" ); document.write( "the area to the left of that z-score is equal to .0008366040026.
\n" ); document.write( "round to 2 decimal places and it becomes 0.\r
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\n" ); document.write( "\n" ); document.write( "i used the TI-84 Plus calculator to get the answers.\r
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\n" ); document.write( "\n" ); document.write( "you can also use the z-score tables, but your z-score would need to be rounded to 2 decimal digits.\r
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\n" ); document.write( "\n" ); document.write( "the z-score table gives you the area to the left of the z-score.
\n" ); document.write( "to get the area to the right of the z-score, you would need to take 1 minus the area to the left of the z-score.\r
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\n" ); document.write( "\n" ); document.write( "there is an online calculator that can also do this directly from the mean and the standard deviation of the raw score as well as from the z-score.\r
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\n" ); document.write( "\n" ); document.write( "that calculator can be found at http://davidmlane.com/hyperstat/z_table.html\r
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\n" ); document.write( "\n" ); document.write( "the results from the use of that calculator, in the order that the the problems were presented, is shown below:\r
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