document.write( "Question 1132796: . Adult tickets cost 5 dollars and child tickets cost 2 dollars. The box office recorded $190 in ticket sales. A total of 50 tickets were sold. How many of those tickets were child tickets?
\n" ); document.write( "Write a system and solve to answer the question. One of your equations is x + y = 50.
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Algebra.Com's Answer #749944 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( ". Adult tickets cost 5 dollars and child tickets cost 2 dollars. The box office recorded $190 in ticket sales. A total of 50 tickets were sold. How many of those tickets were child tickets?
\n" ); document.write( "Write a system and solve to answer the question. One of your equations is x + y = 50.
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Since you want one of the equations to be x + y = 50, then let the number of children's tickets be x, which makes the number of adults' tickets, y
\n" ); document.write( "Then x + y = 50 becomes: y = 50 - x ----- eq (i)
\n" ); document.write( "Then other equation is: 2x + 5y = 190 --- eq (ii)
\n" ); document.write( "5(50 - x) + 2x = 190 ------ Substituting 50 - x for y
\n" ); document.write( "250 - 5x + 2x = 190
\n" ); document.write( "- 5x + 2x = 190 - 250
\n" ); document.write( "- 3x = - 60
\n" ); document.write( "x, or number of children's tickets = \"highlight_green%28matrix%281%2C3%2C+%28-+60%29%2F%28-+3%29%2C+%22=%22%2C+20%29%29\"
\n" ); document.write( "SUBSTITUTION, in this case is much easier than ELIMINATION. Let no-one tell you otherwise! \n" ); document.write( "
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