document.write( "Question 1132758: The circle x^2 + (y-c)^2=r^2, where c >0 and r>0, lies inside the parabola y=x^2. The circle touches the parabola at exactly two points located symmetrically on opposite sides of the y-axis, as shown in the diagram. Deduce that c>1/2\r
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document.write( "so in the diagram, the parabola has vertex (0,0) and is positive for all values of x, and (o,c) is above the two points of intersection.\r
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document.write( "this was 2012 Q16c) HSC question \n" );
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Algebra.Com's Answer #749897 by Edwin McCravy(20059)  You can put this solution on YOUR website! \r\n" );
document.write( "First we find the points of intersection of the circle and\r\n" );
document.write( "parabola by solving the system:\r\n" );
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document.write( "We get this solution:\r\n" );
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document.write( "Since the circle touches the parabola in 2 places, like this:\r\n" );
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document.write( "the value of c must be greater than it is in the case \r\n" );
document.write( "where all four solutions coincide and are equal at the origin (0,0). \r\n" );
document.write( "That is the case when y=0, and r=c\r\n" );
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document.write( "To find c in that case, we setting y=0 and r=c\r\n" );
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document.write( "That is the case when c=r=1/2, therefore we must have c>1/2.\r\n" );
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document.write( "Edwin \n" );
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