document.write( "Question 1132775: 6girls and 2 boys are to be seated in a row.Find the number of ways that this can be done if the 2boys must have exactly 4girls seated between them. \n" ); document.write( "
Algebra.Com's Answer #749892 by greenestamps(13203)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "There are 8 seats; to have 4 girls between the 2 boys, the boys can be in any of three pairs of seats -- 1st and 6th, 2nd and 7th, or 3rd and 8th. So \n" ); document.write( "(1) 3 ways to choose the two seats for the boys. \n" ); document.write( "In those two seats, the two boys can be in either of two orders: \n" ); document.write( "(2) 2 ways to choose which boy is in which seat. \n" ); document.write( "Then the 6 girls can be seated in the remaining 6 seats in 6! ways. \n" ); document.write( "(3) 6!=720 ways to seat the 6 girls. \n" ); document.write( "Total number of ways: 3*2*720 = 4320 \n" ); document.write( " |