document.write( "Question 1132760: An arch in the shape of a parabola has height 630ft and width 630ft. How wide is the arch 300 ft up? \n" ); document.write( "
Algebra.Com's Answer #749880 by MathLover1(20850)\"\" \"About 
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An arch in the shape of a parabola has height \"630ft\" and width \"630ft\". How wide is the arch \"300ft\" up? \r
\n" ); document.write( "\n" ); document.write( "The width of the bridge is \"630\" feet so the parabola crosses the x-axis with x-coordinates ± \"630%2F2\" = ± \"315\"\r
\n" ); document.write( "\n" ); document.write( "=> x-intercepts are at (\"-315\",\"0\") and (\"315\",\"0\")\r
\n" ); document.write( "\n" ); document.write( "Assume that it stands on the x axis, that it is symmetric with respect to the y-axis, and that it is \"630\" feet wide at the base and \"630\" feet high at the \"center\".\r
\n" ); document.write( "\n" ); document.write( " Then the maximum height occurs at \"x+=+0\"; so, the vertex of the parabola is =>(\"0\",\"630\")\r
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\n" ); document.write( "\n" ); document.write( "Since the curve is a parabola which opens downward its equation can be written \r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+a%28x-h%29%5E2+%2Bk\"\r
\n" ); document.write( "\n" ); document.write( "since \"h=0\" and \"k=630\"\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+a%28x-0%29%5E2+%2B630\"\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+ax%5E2+%2B630\"\r
\n" ); document.write( "\n" ); document.write( "x-intercepts are at (\"-315\",\"0\"), use x-intercept to find \"a\"\r
\n" ); document.write( "\n" ); document.write( "\"0+=+a%28-315%29%5E2+%2B630\"\r
\n" ); document.write( "\n" ); document.write( "\"0+=99225%2Aa+%2B630\"\r
\n" ); document.write( "\n" ); document.write( "\"99225+a+=-630\"\r
\n" ); document.write( "\n" ); document.write( "\"+a+=-630%2F99225\"\r
\n" ); document.write( "\n" ); document.write( "\"a+=-2%2F315\"\r
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\n" ); document.write( "\n" ); document.write( "and, equation is\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+-%282%2F315%29x%5E2+%2B630\"\r
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\n" ); document.write( "\n" ); document.write( "to find how wide is the arch \"300ft\" up, substitute \"f%28x%29=+300ft\"\r
\n" ); document.write( "\n" ); document.write( "\"300+=+-%282%2F315%29x%5E2+%2B630\"\r
\n" ); document.write( "\n" ); document.write( "\"%282%2F315%29x%5E2+=630-300\"\r
\n" ); document.write( "\n" ); document.write( "\"%282%2F315%29x%5E2+=330\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+=330%2F%282%2F315%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+=%28330%2A315%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+=165%2A315\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+=51975\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=sqrt%2851975%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x\" = ± \"227.98\"\r
\n" ); document.write( "\n" ); document.write( "the arch \"300\" ft have intercepts at (\"-227.98\",\"300\") and (\"227.98\",\"300\"), so width will be the distance from \"x=-227.98\" to \"x=227.98\" which is \"+2%2A227.98=455.96\" ft\r
\n" ); document.write( "\n" ); document.write( "answer: the arch \"300\" ft up is \"+455.96\" ft wide\r
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