document.write( "Question 1132749: A rectangular field is enclosed by a fence on three sides and a wall on the fourth side. The total length of the
\n" ); document.write( "fence is 320 yards. If the field has a total perimeter of 400 yards, what are the dimensions of the field? \n" ); document.write( "

Algebra.Com's Answer #749875 by ikleyn(52776) $\"\"$ $\"About$

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document.write( "If x and y are the dimensions under the question, then from the condition you have these two equations\r\n" );
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document.write( "    2x +  y = 320     yards   (1)\r\n" );
document.write( "    2x + 2y = 400     yards   (2)\r\n" );
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document.write( "Subtract eq(1) from eq(2). You will get  y = 400-320 = 80 for one dimension  (y).\r\n" );
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document.write( "Then for x you have from eq(1)  2x + 80 = 320  ====>  2x = 320-80 = 240  ====>  x = 240/2 = 120.\r\n" );
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document.write( "ANSWER.  The dimensions are 120 and 80 yards.  80 yards go along the wall.  120 yards go perpendicularly to the wall.\r\n" );
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