document.write( "Question 1132744: A number plus half of another number equals 6; twice the first number minus three times the second number
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Algebra.Com's Answer #749866 by ikleyn(52787)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Let these numbers be x and y.\r\n" );
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document.write( "The description means  \r\n" );
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document.write( "    \"x\" + \"y%2F2\" = 6,         (1)\r\n" );
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document.write( "    2x - 3y = 4.         (2)\r\n" );
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document.write( "Multiply equation (1) by 2; keep equation (2) as is. You will get\r\n" );
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document.write( "    2x +  y = 12          (3)\r\n" );
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document.write( "    2x - 3y = 4.          (4)    (which is the same as (2) )\r\n" );
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document.write( "Subtract equation (4) from equation (3).  The terms \"2x\"  will cancel each other, and you will get a single equation for the unknown y:\r\n" );
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document.write( "       y - (-3y) = 12 - 4,     or\r\n" );
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document.write( "       4y = 8                  =================>  y = 8/4 = 2.\r\n" );
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document.write( "Then from equation (3)  you have 2x + 2 = 12  ====>  2x = 12 - 2 = 10  ====>  x = 10/2 = 5.\r\n" );
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document.write( "ANSWER.  x= 5; y= 2.\r\n" );
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document.write( "The solution will be uncompleted until you CHECK it.\r\n" );
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document.write( "Please do it on your own to make sure that my answer is correct.\r\n" );
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\n" ); document.write( "\n" ); document.write( "In my solution,  I used an elimination method,  so you know now how it works.\r
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\n" ); document.write( "\n" ); document.write( "By the way,  for your safety,  ignore the solution and the answer by  @josgarithmetic,  since they are   W R O N G.\r
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