document.write( "Question 1132722: You invest $6000 in two stocks. In one year, the value of stock A increases by 5.8% and the value of stock B increases by 12.6%. The total value of the stocks is now $6586. How much did you originally invest in each stock \n" ); document.write( "
Algebra.Com's Answer #749840 by ankor@dixie-net.com(22740)\"\" \"About 
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You invest $6000 in two stocks.
\n" ); document.write( "A + B= 6000
\n" ); document.write( "Or
\n" ); document.write( "A =(6000-B)
\n" ); document.write( " In one year, the value of stock A increases by 5.8% and the value of stock B increases by 12.6%.
\n" ); document.write( " The total value of the stocks is now $6586.
\n" ); document.write( "That means the increase amt: 6586 - 6000 = $586
\n" ); document.write( ".058A + .126b = 586
\n" ); document.write( "Replace A with (6000-B)
\n" ); document.write( ".058(6000-B) + .126B = 586
\n" ); document.write( "348 - .058B + .126B = 586
\n" ); document.write( "-.058B + .126B = 586 - 348
\n" ); document.write( ".068B = 238
\n" ); document.write( "B = 238/.068
\n" ); document.write( "B = $3500 in Stock B
\n" ); document.write( "then
\n" ); document.write( "6000 - 3500 = $2500 in Stock A\r
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