document.write( "Question 103139: How many quarts of pure sulphuric acid should be added to 5 quarts of water to obtain a 40% solution? \n" ); document.write( "

Algebra.Com's Answer #74983 by HyperBrain(694) $\"\"$ $\"About$

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Let x=the amt. of sulfuric acid to be added\r
\n" ); document.write( "\n" ); document.write( "NOTE: Total amount(in quarts)*percentage of sulfuric acid(in %)=amount of sulfuric acid(in quarts)\r
\n" ); document.write( "\n" ); document.write( "Also, water does NOT CONTAIN any sulfuric acid so it is ZERO PERCENT acid! Consequently, if the sulfuric acid is defined to be PURE, it is ONE HUNDRED PERCENT acid!\r
\n" ); document.write( "\n" ); document.write( "For the original substance,\r
\n" ); document.write( "\n" ); document.write( " 5*0=0
\n" ); document.write( "For the acid for addition,
\n" ); document.write( " x*100=100x
\n" ); document.write( "and, since it is mixture, the amounts must be added so the amount of the mixture is x+5 quarts! And as defined from the problem, the mixture would be 40 percent acid!\r
\n" ); document.write( "\n" ); document.write( "So,for the mixture,
\n" ); document.write( " 40*(x+5)=40x+200
\n" ); document.write( "Furthermore, the amount of acid is equal to the sum of the amounts of acid of the previous substances, the water and the pure acid.\r
\n" ); document.write( "\n" ); document.write( "Thus,
\n" ); document.write( " 100x+0=40x+200
\n" ); document.write( " 60x=200
\n" ); document.write( " 6x=20
\n" ); document.write( " x=20/6 or 10/3\r
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\n" ); document.write( "\n" ); document.write( "Therefore, 10/3 or 3 1/3 quarts must be added to the 5 quarts of water to produce a solution with 40% sulfuric acid!\r
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\n" ); document.write( "\n" ); document.write( "Please do not hesitate to ask if you need further assistance. Just call my name, HyperBrain! \n" ); document.write( "

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