document.write( "Question 1132704: A genetic experiment with peas resulted in one sample of offspring that consisted of 420 green peas and 159 yellow peas.
\n" ); document.write( "a. Construct a 90​% confidence interval to estimate of the percentage of yellow peas.
\n" ); document.write( "b. It was expected that​ 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not​ 25%, do the results contradict​ expectations?
\n" ); document.write( "a. Construct a 90​% confidence interval. Express the percentages in decimal form.\r
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\n" ); document.write( "nothing ​(Round to three decimal places as​ needed.) \n" ); document.write( "


Algebra.Com's Answer #749823 by Boreal(15235)\"\" \"About 
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90% half-interval is z*sqrt(p*(1-p)/n) where z=1.645 and p is the point estimate of yellow or 159/579=0.275
\n" ); document.write( "half-interval is 1.645* sqrt (0.275*0.725/579)=0.0301
\n" ); document.write( "Therefore, the full interval is 0.275+/-1.645* sqrt (0.275*0.725/579)
\n" ); document.write( "the interval is (0.245, 0.305)
\n" ); document.write( "because 0.25 is within the confidence interval, the results to not contradict expectations.
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