document.write( "Question 103129: If $4000 is invested at 6%, how much must be invested at 3% so that the total annual income will be $270? \n" ); document.write( "
Algebra.Com's Answer #74980 by chitra(359)\"\" \"About 
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It is given that $ 4000 is invested at 6% \r
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\n" ); document.write( "\n" ); document.write( "So that we get $240. \r
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\n" ); document.write( "\n" ); document.write( "We will have to find What amount must be invested at 3% to make the total equals $270.\r
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\n" ); document.write( "\n" ); document.write( "so 3 % of x = 30\r
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\n" ); document.write( "\n" ); document.write( "==> \"%283%2F100%29+%2A+x+=++30\" \r
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\n" ); document.write( "\n" ); document.write( "==> 3x = 30 * 100\r
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\n" ); document.write( "\n" ); document.write( "==> \"x+=+%2830+%2A+100%29%2F3+\" \r
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\n" ); document.write( "\n" ); document.write( "==> x = 1000 \r
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\n" ); document.write( "\n" ); document.write( "So we must invest $ 1000 to make the total income equal to $270.\r
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\n" ); document.write( "\n" ); document.write( "Thus the solution.\r
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