document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=15084>Question 15084</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i dont understand these guestions..can i please get some help\r<BR>\n" );
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document.write( "2. a) David works part-time for a bike repair shop. He earns $1 for each tire he installs and $4 for each gear mechanism he assembles. If he did a total of 50 insatallations and assemblies and earned $92, how many tires did he install?\r<BR>\n" );
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document.write( "b) A car rental angency rents cars under two plans:<BR>\n" );
document.write( "Plan 1: $55 per day and $0.10/km<BR>\n" );
document.write( "Plan 2: $40 per day and $0.25/km<BR>\n" );
document.write( "Determine when both plans will result in the same charge for a one-day rental. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7498 by </B><A HREF=/tutors/aboutme.mpl?userid=bam878s><B>bam878s(77)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bam878s><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7498\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (a)<BR>\n" );
document.write( "Let x = total number of tires he installs<BR>\n" );
document.write( "and y = total number of gear mechanisms assembled.<BR>\n" );
document.write( "We have, <BR>\n" );
document.write( "x + y = 50 and<BR>\n" );
document.write( "x + 4y = 92.  If we subtract the first equation from the second equation we get<BR>\n" );
document.write( "3y = 42. Now divide by 3 to solve for y<BR>\n" );
document.write( "y = 14.  So he assembled 14 gear mechanisms.  To find out the number of tires we simply plug this value of y into one of the original two equations and solve for x<BR>\n" );
document.write( "x + 14 = 50. Subtract 14 from both sides.<BR>\n" );
document.write( "x = 36 tires he intalled.<BR>\n" );
document.write( "(b)<BR>\n" );
document.write( "Let x = number of km.<BR>\n" );
document.write( "To solve for this one we simply set the equations equal to each other and solve for x.<BR>\n" );
document.write( "55 + .10x = 40 + .25x<BR>\n" );
document.write( "15 = .15x<BR>\n" );
document.write( "divide by .15<BR>\n" );
document.write( "100 = x.<BR>\n" );
document.write( "So after 100 km, the charge will be the same. </SPAN>\n" );
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