document.write( "Question 1132663: A surprising number of people are scared of clowns. You expect that people will have more nightmares the night that they see clowns at the circus. To test this, you send a group of people to a circus with clowns, and a group to a circus without clowns, and measure the number of people in each group who have nightmares that night. Your data is shown below:\r
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document.write( " Nightmares Nice dreams
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document.write( "No clowns 12 35
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document.write( "Clowns 30 8
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document.write( "Perform a Z-test on nightmares after the no-clown circus minus nightmares after the clown circus. Report the test statistic.\r
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Algebra.Com's Answer #749792 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Your data is shown below: \n" ); document.write( "..........Nightmares Nice dreams \n" ); document.write( "No clowns 12 35 \n" ); document.write( "Clowns 30 8 \n" ); document.write( "--- \n" ); document.write( "p1 = 12/47 \n" ); document.write( "p2 = 30/38 \n" ); document.write( "---- \n" ); document.write( "Perform a Z-test on nightmares after the no-clown circus minus nightmares after the clown circus. Report the test statistic. \n" ); document.write( "--- \n" ); document.write( "Ho:: p1-p2 = 0 \n" ); document.write( "Ha:: p1-p2 # 0 \n" ); document.write( "----- \n" ); document.write( "Sample difference:: 12/47-30/38 = -0.534 \n" ); document.write( "Standard deviation = sqrt[(12/47)(25/47)/47 + (30/38)(8/38)/38] \n" ); document.write( "= sqrt[0.0029+0.0044] = 0.0853 \n" ); document.write( "--- \n" ); document.write( "Test Statistic:: z(-0.534) = -0.523/0.0853 = -6.132 \n" ); document.write( "----\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |