document.write( "Question 1132636: Find the vector projection of u onto v. Then write u as the sum of two orthogonal vectors, one of which is proj(Subscript v)u.\r
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Algebra.Com's Answer #749736 by MathLover1(20850) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"u\"$ = < $\"2\"$ , $\"8\"$ >, $\"v\"$ =< $\"4\"$ , $\"-5\"$ >\r
\n" ); document.write( "\n" ); document.write( " $\"proj%5Bv%5Du=%28u%2Av%29%2F%28abs%28u%29%29%5E2\"$ *< $\"4\"$ , $\"-5\"$ >\r
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\n" ); document.write( "\n" ); document.write( " $\"u%2Av=+8%E2%80%8B-40=-32\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%28abs%28u%29%29%5E2=%28sqrt%284%5E2%2B5%5E2%29%29%5E2=%28sqrt%2841%29%29%5E2\"$ \r
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\n" ); document.write( "\n" ); document.write( "substitute in $\"proj%5Bv%5Du=%28u%2Av%29%2F%28abs%28u%29%29%5E2\"$ *< $\"4\"$ , $\"-5\"$ >\r
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\n" ); document.write( "\n" ); document.write( " $\"proj%5Bv%5Du\"$ = $\"-32%2F%28sqrt%2841%29%29%5E2\"$ *< $\"4\"$ , $\"-5\"$ >\r
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\n" ); document.write( "\n" ); document.write( " $\"proj%5Bv%5Du\"$ =( $\"-32%2F41\"$ )*< $\"4%E2%80%8B\"$ , $\"-5\"$ >\r
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\n" ); document.write( "\n" ); document.write( "proj[v]u=( $\"-32%2F41%294%E2%80%8B\"$ ,( $\"-32%2F41%29%28-5%29\"$ )\r
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\n" ); document.write( "\n" ); document.write( " $\"proj%5Bv%5Du\"$ =( $\"-128%2F41\"$ , $\"160%2F41\"$ )\r
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