document.write( "Question 1132643: 1/(x-1)^2+1/x-1=12 \n" ); document.write( "
Algebra.Com's Answer #749735 by ikleyn(52780)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "            See how I edited your post to make it  unambigous:\r
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document.write( "              1/(x-1)^2 + 1/(x-1) = 12    <<<---=== I added parentheses !\r\n" );
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document.write( "Introduce new variable  z = \"1%2F%28x-1%29\".\r\n" );
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document.write( "Then your original equation takes the form\r\n" );
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document.write( "    \"z%5E2+%2B+z\" = 12,    or\r\n" );
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document.write( "    \"z%5E2+%2B+z+-+12\" = 0.\r\n" );
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document.write( "Factor left side\r\n" );
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document.write( "    (z-3)*(z+4) = 0.\r\n" );
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document.write( "The two roots for z are  z= 3  and  z= -4.\r\n" );
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document.write( "Now we have two cases to analyse separately.\r\n" );
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document.write( "    Case 1.  z= 3  ====>  \"1%2F%28x-1%29\" = 3  ====>  x-1 = \"1%2F3\"  ====>  x= \"1\"\"1%2F3\".\r\n" );
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document.write( "    Case 2.  z= -4  ====>  \"1%2F%28x-1%29\" = -4  ====>  x-1 = \"-1%2F4\"  ====>  x= \"3%2F4\".\r\n" );
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document.write( "ANSWER.  There are two solutions  x= \"1\"\"1%2F3\"  and  x= \"3%2F4\".\r\n" );
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