document.write( "Question 103123This question is from textbook Intermediate Algebra
\n" ); document.write( ": Help!!
\n" ); document.write( "How much of a 40% antifreeze solution must a mechanic mix with an 80% antifreeze solution if 20 gallons of a 50% antifreeze solution are needed? \n" ); document.write( "
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How much of a 40% antifreeze solution must a mechanic mix with an 80% antifreeze solution if 20 gallons of a 50% antifreeze solution are needed?
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\n" ); document.write( "Let amt of 80% solution be x gallons: amt of active ingredient= 0.80x gallons
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\n" ); document.write( "Amt of 40% solution is \"20-x\" gals; amt of active is 0.4(20-x)=8-0.4x gallons
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\n" ); document.write( "Amt of 50% mixture is 20 gals: amt of active ingredient =0.5*20=10 gallons
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\n" ); document.write( "EQUATION:
\n" ); document.write( "active + active = active
\n" ); document.write( "0.8x + 8 - 0.4x = 10
\n" ); document.write( "0.4x = 2
\n" ); document.write( "x = 5 gallons (amt of 80% antifreeze in the mixture)
\n" ); document.write( "20-x = 15 gallong (amt of 40% antifreeze in the mixture)
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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