document.write( "Question 1132517: The general expression for consecutive multiples of seven 7n, 7(n+1), 7(n+2)where n is some unspecified integer. Find three consecutive multiples of seven such that the product of -3 and the sum of the first and third is 21 less than five times opposite of a second. \n" ); document.write( "

Algebra.Com's Answer #749579 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
The general expression for consecutive multiples of seven 7n, 7(n+1), 7(n+2)where n is some unspecified integer.
\n" ); document.write( " Find three consecutive multiples of seven such that the product of -3 and the sum of the first and third is 21 less than five times opposite of a second.
\n" ); document.write( ":
\n" ); document.write( "-3(7n+7(n+2)) = -5(7(n+1)) - 21
\n" ); document.write( "-3(7n + 7n + 14) = -5(7n + 7) -21
\n" ); document.write( "-3(14n + 14) = -35n - 35 - 21
\n" ); document.write( "-42n - 42 = -35n - 56
\n" ); document.write( "multiply by -1
\n" ); document.write( "42n + 42 = 35n + 56
\n" ); document.write( "42n - 35n = 56 -42
\n" ); document.write( "7n = 14
\n" ); document.write( "n = 2
\n" ); document.write( "The three consecutive multiples of 7: 7(2), 7(3), 7(4) or
\n" ); document.write( "14, 21, 28
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See if that works
\n" ); document.write( "-3((14) + (28)) = 5(-21) - 21
\n" ); document.write( "-3(42) = -105 - 21
\n" ); document.write( "-26 = -26\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );