document.write( "Question 1132483: The measure of the supplement of angle A is 40 degrees larger than twice the measure of the complement of angle A. What is the sum in degree of the measures of the supplement and complement of angle A? \n" ); document.write( "

Algebra.Com's Answer #749561 by Edwin McCravy(20056) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "The measure of the supplement of angle A...
\n" ); document.write( "

\r\n" );
document.write( "That's 180°-A\r\n" );
document.write( "\r\n" );
document.write( "So far we have -->                    180°-A\r\n" );
document.write( "

\n" ); document.write( "...is...
\n" ); document.write( "

\r\n" );
document.write( "That's equal =\r\n" );
document.write( "\r\n" );
document.write( "So far we have -->                     180°-A =\r\n" );
document.write( "

\n" ); document.write( "...40 degrees larger than...
\n" ); document.write( "

\r\n" );
document.write( "that means that we are to add 40° onto what's after \"than\"\r\n" );
document.write( "\r\n" );
document.write( "So far we have -->                     180°-A =          +40°  \r\n" );
document.write( "(skipping a space for what's after \"than\"): \r\n" );
document.write( "

\n" ); document.write( "...twice...
\n" ); document.write( "

\r\n" );
document.write( "That means that what's after \"than\" starts with 2× (*two times\") \r\n" );
document.write( "\r\n" );
document.write( "So far we have -->                     180°-A = 2×       +40°\r\n" );
document.write( "

\n" ); document.write( "...the measure of the complement of angle A...
\n" ); document.write( "

\r\n" );
document.write( "That's (90°-A), so that's what we put after the 2× and before\r\n" );
document.write( "the +40°\r\n" );
document.write( "\r\n" );
document.write( "Now we have the finished equation: \r\n" );
document.write( "                                       180°-A = 2×(90°-A)+40°\r\n" );
document.write( "\r\n" );
document.write( "So we solve it\r\n" );
document.write( "\r\n" );
document.write( "Distribute the 2×\r\n" );
document.write( "\r\n" );
document.write( "                                       180°-A = 2×90°-2×A+40°\r\n" );
document.write( "Multiply 2×90° get 180°\r\n" );
document.write( "                                       180°-A = 180°-2A+40°\r\n" );
document.write( "\r\n" );
document.write( "Subtract 180° from both sides:\r\n" );
document.write( "\r\n" );
document.write( "                                           -A = -2A+40°\r\n" );
document.write( "\r\n" );
document.write( "Add 2A to both sides\r\n" );
document.write( "\r\n" );
document.write( "                                            A = 40°\r\n" );
document.write( "

\n" ); document.write( "...What is the sum in degree of the measures of the supplement...
\n" ); document.write( "

\r\n" );
document.write( "That's 180°-A\r\n" );
document.write( "       180°-40°\r\n" );
document.write( "       140°\r\n" );
document.write( "

\n" ); document.write( "...and complement of angle A?...
\n" ); document.write( "

\r\n" );
document.write( "That's 90°-A\r\n" );
document.write( "       90°-40°\r\n" );
document.write( "       50°\r\n" );
document.write( "\r\n" );
document.write( "Edwin

\n" ); document.write( "

\n" );