document.write( "Question 1132497: You invested $13000 in two accounts paying \r
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document.write( "2% and
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document.write( "6 %
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document.write( "annual interest, respectively.
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document.write( "If the total interest earned for the year was
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document.write( "$380, how much was invested at each rate? \n" );
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Algebra.Com's Answer #749542 by addingup(3677)![]() ![]() You can put this solution on YOUR website! Let the amount invested at 2% be x \n" ); document.write( "Then, the amount invested at 6% is 13000 - x \n" ); document.write( ". \n" ); document.write( "0.02x + 0.06(13000 - x) = 380 \n" ); document.write( "0.02x + 780 - 0.06x = 380 \n" ); document.write( "-0.04x = -400 \n" ); document.write( "x = -400/-0.04 = divide, remember that -/- = + so you can ignore the - sign when you divide. \n" ); document.write( "This will be the amount invested at 2%. Subtract the amount from 13000 to find out the amount invested at 6%.\r \n" ); document.write( "\n" ); document.write( ". \n" ); document.write( "Happy learning \n" ); document.write( " |