document.write( "Question 1132492: an arrow is shot vertically upward with a speed of 288ft/s, and 3.00 s later another is shot up at a speed of 240 ft/s. will they meet? If so, where? \n" ); document.write( "
Algebra.Com's Answer #749533 by Alan3354(69443)\"\" \"About 
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arrow is shot vertically upward with a speed of 288ft/s, and 3.00 s later another is shot up at a speed of 240 ft/s. will they meet? If so, where?
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\n" ); document.write( "Using 32 ft/sec/sec for gravity:
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\n" ); document.write( " will they meet?
\n" ); document.write( "The 1st arrows height h(t) = -16t^2 + 288t
\n" ); document.write( "At t = 3 seconds, h(3) = -16*9 + 288*3 = 720 feet
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\n" ); document.write( "Its speed = 288 - 3*32 = 192 ft/sec
\n" ); document.write( "From that point, its height = -16t^2 + 192t + 720
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\n" ); document.write( "The 2nd arrows height = -16t^2 + 240t
\n" ); document.write( "When the 2nd arrow is launched, the 1st arrows height = -16t^2 + 192t + 720
\n" ); document.write( "Find where the 2 heights are equal.
\n" ); document.write( "-16t^2 + 192t + 720 = -16t^2 + 240t
\n" ); document.write( "48t = 720
\n" ); document.write( "t = 15 seconds --- that's 15 seconds from the 2nd launch.
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\n" ); document.write( "For the 1st arrow: h = -16*18^2 + 288*18 = 0 feet AGL
\n" ); document.write( "For the 2nd arrow: h = -16*15^2 + 240*15 = 0
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\n" ); document.write( "They meet at impact, 18 seconds after the 1st launch
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