document.write( "Question 1132480: Jessa is 15 years older than her student.In 15 years, twice her age will be thrice the age of her student.Find the present age of her student. \n" ); document.write( "
Algebra.Com's Answer #749528 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "(1) The difference in their ages will always be 15 years.

\n" ); document.write( "(2) In 15 years, twice her age will be thrice the age of her student. In other words, her age will be 3/2 of her student's age.

\n" ); document.write( "(3) 3/2 her student's age, with an age difference of 15 years, will be when she is 45 and her student is 30.

\n" ); document.write( "(4) Since that will be 15 years from now, she is now 30 and her student is now 15.
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