document.write( "Question 1132454: the probability that 3boys passed an exam are 2/3,5/8,3/4 respectively.find the probability that all the three boys passed and also the probability that none of the three boys passed .fin
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Algebra.Com's Answer #749503 by Edwin McCravy(20077)\"\" \"About 
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document.write( "P(all 3 passed) = (2/3)(5/8)(3/4)\r\n" );
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document.write( "P(none passed) =  (1-2/3)(1-5/8)(1-3/4) = (1/3)(3/8)(1/4) = 1/32\r\n" );
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document.write( "P(exactly 2 passed) = \r\n" );
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document.write( "P(1st and 2nd passed but 3rd did not pass) +\r\n" );
document.write( "P(1st and 3rd passed but 2nd did not pass) +\r\n" );
document.write( "P(2nd and 3rd passed but 1st did not pass) =\r\n" );
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document.write( "(2/3)(5/8)(1-3/4) + (2/3)(1-5/8)(3/4) + (1-2/3)(5/8)(3/4) =\r\n" );
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document.write( "(2/3)(5/8)(1/4) + (2/3)(3/8)(3/4) + (1/3)(5/8)(3/4) = 43/96\r\n" );
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document.write( "Edwin
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