document.write( "Question 1132438: The sum of three numbers in Ap is 39 and the sum of their product is 2184.find the number \n" ); document.write( "
Algebra.Com's Answer #749495 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The statement of the problem is indeed faulty; but the other tutor who tried to answer the question revised the statement of the problem in a way that made a solution impossible (and the algebra involved in TRYING to solve the problem difficult).

\n" ); document.write( "A different correction to the statement of the problem gives a problem that is relatively easy to solve:

\n" ); document.write( "The sum of three numbers in Ap is 39 and \"highlight%28cross%28the+sum+of%29%29\" their product is 2184.find the number

\n" ); document.write( "Given that the sum of three numbers in arithmetic progression is 39, the middle number is 13. So the numbers are 13-x, 13, and 13+x.

\n" ); document.write( "There are many ways to solve the problem from there. Probably the easiest is to recognize that (13-x)(13)(13+x) is \"close\" to 13^3; and 13^3 = 2197. That makes it highly likely that x=1; and indeed 12*13*14 = 2184.
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