document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1132453>Question 1132453</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2(2x + 3)<BR>\n" );
document.write( "---------  + 3<BR>\n" );
document.write( "3x - 2\r<BR>\n" );
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document.write( "-------------<BR>\n" );
document.write( "2(2x + 3)<BR>\n" );
document.write( "---------  - 2<BR>\n" );
document.write( "3x - 2\r<BR>\n" );
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document.write( "Put in simplest form.\r<BR>\n" );
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document.write( "Unsure how to continue.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #749494 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=749494\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "look at the numerator and write both over 3x-2 as a denominator<BR>\n" );
document.write( "that is 2(2x+3)+3(3x-2), which equals 4x+6+9x-6, or 13x/3x-2\r<BR>\n" );
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document.write( "the denominator written of 3x-2 is 2(2x+3)-2(3x-2), or 4x+6-6x+4 or -2x+10/3x-2<BR>\n" );
document.write( "Both the numerator and denominator each have a 3x-2 in the denominator, so that may be removed\r<BR>\n" );
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document.write( "13x/(-2x+10) is the answer\r<BR>\n" );
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document.write( "plug 3 in for x, and the answer is 39/4 in the original and the simplified form.<BR>\n" );
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