document.write( "Question 1132434: If choosing two numbers between 25 and 225, what is the probability of choosing two numbers that are divisible by 4 but not divisible by either 6 or 10? \n" ); document.write( "

Algebra.Com's Answer #749491 by Boreal(15235) $\"\"$ $\"About$

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there are 201 numbers.
\n" ); document.write( "fifty of them (1/4) are divisible by 4\r
\n" ); document.write( "\n" ); document.write( "One third of those divisible by 4 are divisible by 6 as well, and two-thirds of 50 is 33\r
\n" ); document.write( "\n" ); document.write( "some additional are divisible by 10 and not 6 (40, 80, 100, 140,160,200, 220) leaving 26\r
\n" ); document.write( "\n" ); document.write( "the numbers left from 25-100 inclusive are
\n" ); document.write( "28/32/44/52/56/64/68/76/88/92 for 10 numbers
\n" ); document.write( "look now at
\n" ); document.write( "104/108/112/116/124/128/132/136/144/148/152/156/164/168/176/188/192/196, and 108, 132, 144, 156, 168, 192 are excluded, so there are 12 left
\n" ); document.write( "204/208/212/216/220/224 --exclude 204 and 216 for 4
\n" ); document.write( "The total number is 26
\n" ); document.write( "probability of choosing one is 26/201 and the second would be 25/200
\n" ); document.write( "that joint probability is 0.016\r
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