document.write( "Question 1132440: A rectangle dog kennel is to be constructed alongside a house with 60 m of fencing. If the house serves as one side of the kennel, determine the greatest possible area that can be enclosed. \n" ); document.write( "
Algebra.Com's Answer #749472 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Let the width of the kennel (perpendicular to the side of the house) be x. Then with a total of 60m of fencing, the length is 60-2x.

\n" ); document.write( "The area of the kennel is then

\n" ); document.write( "\"x%2860-2x%29+=+-2x%5E2%2B60x\"

\n" ); document.write( "Then find the value of x that maximizes the area either using calculus, or by knowing that the value of x that maximizes ax^2+bx+c is x = -b/2a.

\n" ); document.write( "Then remember that the value of x is not the answer to the question; you need to use it to find the maximum area.
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