document.write( "Question 1132373: in 3 years angelo will be 3x as old as his sister Precy, a year ago angelo was 7 times as old as precy how old are they now \n" ); document.write( "
Algebra.Com's Answer #749435 by Theo(13342)\"\" \"About 
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let a equal the age of angelo totday.
\n" ); document.write( "let p equal the ager of precy today.\r
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\n" ); document.write( "\n" ); document.write( "in 3 years angelo will be 3 times as old as precy.\r
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\n" ); document.write( "\n" ); document.write( "equation for that is a + 3 = 3 * (p + 3).\r
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\n" ); document.write( "\n" ); document.write( "a year ago angelo was 7 times as old as precy.\r
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\n" ); document.write( "\n" ); document.write( "equation for that is a - 1 = 7 * (p - 1).\r
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\n" ); document.write( "\n" ); document.write( "you have two equations that need to be solved simultaneously.\r
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\n" ); document.write( "\n" ); document.write( "they are:\r
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\n" ); document.write( "\n" ); document.write( "a + 3 = 3 * (p + 3)
\n" ); document.write( "a - 1 = 7 * (p - 1)\r
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\n" ); document.write( "\n" ); document.write( "simplify both equations to get:\r
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\n" ); document.write( "\n" ); document.write( "a + 3 = 3 * p + 9
\n" ); document.write( "a - 1 = 7 * p - 7\r
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\n" ); document.write( "\n" ); document.write( "place the variables on the let side of the equal sign and the constants on the right side of the equal sign to get:\r
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\n" ); document.write( "\n" ); document.write( "a - 3 * p = 9 - 3
\n" ); document.write( "a - 7 * p = -7 + 1\r
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\n" ); document.write( "\n" ); document.write( "combine like terms in both equations to get:\r
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\n" ); document.write( "\n" ); document.write( "a - 3 * p = 6
\n" ); document.write( "a - 7 * p = -6\r
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\n" ); document.write( "\n" ); document.write( "subtract the second equation from the first to get:\r
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\n" ); document.write( "\n" ); document.write( "4 * p = 12\r
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\n" ); document.write( "\n" ); document.write( "solve for p to get p = 12 / 4 = 3\r
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\n" ); document.write( "\n" ); document.write( "that's precy's age today.\r
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\n" ); document.write( "\n" ); document.write( "replace p with 3 in either of the original equations as shown below.\r
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\n" ); document.write( "\n" ); document.write( "the two original equations are:\r
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\n" ); document.write( "\n" ); document.write( "a + 3 = 3 * (p + 3)
\n" ); document.write( "a - 1 = 7 * (p - 1)\r
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\n" ); document.write( "\n" ); document.write( "the first equation becomes a + 3 = 3 * 6 which a + 3 = 18 which becomes a = 15.\r
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\n" ); document.write( "\n" ); document.write( "the second equation becomes a - 1 = 7 * 2 which becomes a - 1 = 14 which becomes a = 15.\r
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\n" ); document.write( "\n" ); document.write( "that's the age of angelo today.\r
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\n" ); document.write( "\n" ); document.write( "you have:\r
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\n" ); document.write( "\n" ); document.write( "a = 15
\n" ); document.write( "p = 3\r
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\n" ); document.write( "\n" ); document.write( "in 3 years, a = 18 and p = 6 which makes a = 3 times p.\r
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\n" ); document.write( "\n" ); document.write( "one year ago, a was 14 and p was 2 which made a = 7 times p.\r
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\n" ); document.write( "\n" ); document.write( "solution looks good.\r
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\n" ); document.write( "\n" ); document.write( "solution is:\r
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\n" ); document.write( "\n" ); document.write( "angelo is 15 years old and precy is 3.\r
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