document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=103093>Question 103093</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given g(x) = 5x – 2, find g(3a).\r<BR>\n" );
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document.write( "HELP I have no idea how to do this problem and no one else seems to be able to tell me how to  do it either. Can someone help please? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74942 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74942\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The idea here is to substitute the new value into the function.\r<BR>\n" );
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document.write( "Usually, f(x) is the function, but this time it is g(x).\r<BR>\n" );
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document.write( "We are told, g(x) = 5x - 2.\r<BR>\n" );
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document.write( "That is the function. Think of it like a machine that takes some input and multiplies it by 5 and then subtracts 2: Input x and out comes 5x-2.\r<BR>\n" );
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document.write( "Here were are told to find g(3a), so they are telling us that x=3a. Simply substitute: Plug in 3a to the \"function machine\" and out comes 5 times 3a - 2:\r<BR>\n" );
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document.write( "g(3a) = 5(3a) - 2\r<BR>\n" );
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document.write( "g(3a) = 15a - 2<BR>\n" );
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