document.write( "Question 1132385: Jack and Jill are traveling to Orlando. The trip take 2hrs for Jack and 3.5hrs for Jill, since she lives 80mi farther. Jill travels 10mph faster than Jack. Find the speed of Jack \n" ); document.write( "
Algebra.Com's Answer #749407 by ikleyn(52865) You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Let x be the speed of Jack.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then the distance Jack traveled during 2 hours was 2x.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Jill traveled 80 miles more, so she traveled (2x+80) miles.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Her speed was (x+10) miles per hour.\r\n" ); document.write( "\r\n" ); document.write( "She spent 3.5 hours, hence\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 3.5*(x+10) = 2x + 80.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Solve the equation\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 3.5x + 35 = 2x + 80\r\n" ); document.write( "\r\n" ); document.write( " 3.5x - 2x = 80 - 35\r\n" ); document.write( "\r\n" ); document.write( " 1.5x = 45\r\n" ); document.write( "\r\n" ); document.write( " x =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |