document.write( "Question 1132346: angle PQR = angle PSQ = 90° |PS| =9cm, |SR| =16cm. calculate the value of SQ and and angle QRS.
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Algebra.Com's Answer #749364 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " if $\"PSQ+=+90\"$ °, than $\"RSQ=90\"$ °\r
\n" ); document.write( "\n" ); document.write( "=> triangle $\"PSR+\"$ is similar to triangle $\"RSQ\"$ , corresponding sides are proportional\r
\n" ); document.write( "\n" ); document.write( "=> side $\"SR=+16cm\"$ is common side\r
\n" ); document.write( "\n" ); document.write( "=> $\"+SR%2FPS=SR%2FSQ\"$ \r
\n" ); document.write( "\n" ); document.write( "=> $\"16%2F9=16%2FSQ\"$ \r
\n" ); document.write( "\n" ); document.write( "=> $\"16SQ=16%2A9\"$ \r
\n" ); document.write( "\n" ); document.write( "=> $\"SQ=16%2A9%2F16\"$ \r
\n" ); document.write( "\n" ); document.write( "=> $\"SQ=9cm\"$ \r
\n" ); document.write( "\n" ); document.write( "then angle $\"QRS\"$ is: \r
\n" ); document.write( "\n" ); document.write( " $\"tan%28QRS%29=SQ%2FSR=9%2F16=0.5625\"$ \r
\n" ); document.write( "\n" ); document.write( "angle $\"QRS=tan%5E-1%280.5625%29=29.36\"$ °\r
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