document.write( "Question 1132334: Can you help me with this problem, please:
\n" ); document.write( "Each letter in this addition problem stands for a different digit and every letter stands for the same digit everywhere it appears. Find the value of SKIP.
\n" ); document.write( " I
\n" ); document.write( " IRK
\n" ); document.write( "+SIR
\n" ); document.write( "____
\n" ); document.write( "SKIP\r
\n" ); document.write( "\n" ); document.write( "I think that S should be 1, but how to solve all the problem
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Algebra.Com's Answer #749345 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!

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document.write( "        I\r\n" );
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document.write( "    I R K\r\n" );
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document.write( "  + S I R\r\n" );
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document.write( "  -------\r\n" );
document.write( "  S K I P

\n" ); document.write( "Yes, S has to be 1, because the sum of two 3-digit numbers and a 1-digit number can't be more than 1999.

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document.write( "        I\r\n" );
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document.write( "    I R K\r\n" );
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document.write( "  + 1 I R\r\n" );
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document.write( "  -------\r\n" );
document.write( "  1 K I P

\n" ); document.write( "Now with S=1, K (in SKIP) has to be either 1 or 0; but it can't be 1, because S is 1; so K is 0.
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document.write( "        I\r\n" );
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document.write( "    I R 0\r\n" );
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document.write( "  + 1 I R\r\n" );
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document.write( "  -------\r\n" );
document.write( "  1 0 I P

\n" ); document.write( "I'll show you a path to finishing the problem from here and let you do the actual work....

\n" ); document.write( "In the tens column, with R plus I giving digit I in the sum, there are only two possible values for R; but one of them has already been used. So you know what R has to be.

\n" ); document.write( "Now in the hundreds column I plus S (=1) giving K (=0) in the sum leaves only two possible values for K; but one of them has already been used. So now you know what K has to be.

\n" ); document.write( "Then the only thing left to do is perform the addition to find the value of P.
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